PHP Dokumentation: Mysqli-stmt param-count
12. Januar 2010 von werner
mysqli_stmt->param_count
mysqli_stmt_param_count
(PHP 5)
mysqli_stmt->param_count — mysqli_stmt_param_count — Returns the number of parameter for the given statement
Beschreibung
Object oriented style (property):
int $param_count;
Procedural style:
int mysqli_stmt_param_count ( mysqli_stmt $stmt )
Returns the number of parameter markers present in the prepared statement.
Parameter-Liste
- stmt
Nur bei prozeduralem Aufruf: ein vonmysqli_stmt_init() zurückgegebensStatementobjekt.
Rückgabewerte
Returns an integer representing the number of parameters.
Beispiele
Beispiel #1 Object oriented style
<?php
$mysqli = new mysqli("localhost", "my_user", "my_password", "world");/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}if (
$stmt = $mysqli->prepare("SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = $stmt->param_count;
printf("Statement has %d markers.\n", $marker);
/* close statement */
$stmt->close();
}/* close connection */
$mysqli->close();
?>Beispiel #2 Procedural style
<?php
$link = mysqli_connect("localhost", "my_user", "my_password", "world");/* check connection */
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}if (
$stmt = mysqli_prepare($link, "SELECT Name FROM Country WHERE Name=? OR Code=?")) {
$marker = mysqli_stmt_param_count($stmt);
printf("Statement has %d markers.\n", $marker);
/* close statement */
mysqli_stmt_close($stmt);
}/* close connection */
mysqli_close($link);
?>Das oben gezeigte Beispiel erzeugt folgendeAusgabe:
Statement has 2 markers.
Siehe auch
- mysqli_prepare() – Prepare a SQL statement for execution
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